Eureka Math Grade 3 Module 3 Lesson 17 Answer Key
Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.
Engage NY Eureka Math 3rd Grade Module 3 Lesson 17 Answer Key
Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.
Eureka Math Grade 3 Module 3 Lesson 17 Problem Set Answer Key
a. Color all the squares with even products orange. Can an even product ever have an odd factor?
Answer: 1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.
b. Can an odd product ever have an even factor?
Answer: No, an odd product ever has an even factor.
Explanation: In the above-given question, given that, 1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64. No, an odd product ever has an even factor.
c. Everyone knows that 7 × 4 = (5 × 4) + (2 × 4). Explain how this is shown in the table.
Answer: 7 x 4 = 28. 5 x 4 = 20. 2 x 4 = 8. 20 + 8 = 28.
Explanation: In the above-given question, given that, 7 x 4 = 28. 5 x 4 = 20. 2 x 4 = 8. 20 + 8 = 28.
d. Use what you know to find the product of 7 × 16 or 8 sevens + 8 sevens.
Answer: 7 x 16 = 112.
Explanation: In the above-given question, given that, 7 x 6 = 112. 8 sevens + 8 sevens. 8 x 7 + 8 x 7. 56 + 56. 112.
Answer: 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 2 x 1 = 2, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 3 x 1 = 3, 3 x 2 = 6, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 5 = 20, 4 x 6 = 24, 5 x 1 = 5, 5 x 2 = 1, 5 x 3 = 15, 5 x 4 = 20, 5 x 6 = 30, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30.
b. Draw an array to match each expression in the table below. Then, label the number of squares you added to make each new array. The first two arrays have been done for you.
Answer: 1 + 2 = 3. 3 + 6 = 9. 6 + 10 = 16. 10 + 15 = 25. 15 + 21 = 36.
c. What pattern do you notice in the number of squares that are added to each new array?
Answer: 1 + 3 = 4. 4 + 6 = 9. 6 + 10 = 16. 10 + 15 = 25. 15 + 21 = 36.
Explanation: In the above-given question, given that, 1 + 3 = 4. 4 + 6 = 9. 6 + 10 = 16. 10 + 15 = 25. 15 + 21 = 36.
d. Use the pattern you discovered in Part (b) to prove this: 9 × 9 is the sum of the first 9 odd numbers.
Answer: 9 x 9 = 81.
Explanation: In the above-given question, given that, 9 x 9 = 81. the sum of the first 9 odd numbers is 81. 9 x 9 = 81.
Eureka Math Grade 3 Module 3 Lesson 17 Exit Ticket Answer Key
Question 1. Use what you know to find the product of 8 × 12 or 6 eights + 6 eights.
Answer: 8 x 12 = 96.
Explanation: In the above-given question, given that, 8 x 12 = 96. 6 eights + 6 eights. 6 x 8 + 6 x 8. 48 + 48. 96.
Question 2. Luis says 3 × 233 = 626. Use what you learned about odd times odd to explain why Luis is wrong.
Answer: 3 x 233 = 626.
Explanation: In the above-given question, given that, 3 x 233 = 626. odd x odd = odd. but in the given question, Luis is wrong. 3 x 233 = 626. 625 + 1.
Eureka Math Grade 3 Module 3 Lesson 17 Homework Answer Key
b. Color the rows and columns with even factors yellow.
Answer: The even factors are color with yellow.
c. What do you notice about the factors and products that are left unshaded
Answer: The factors that are left unshaded is odd numbers.
Explanation: In the above-given question, given that, the factors that are left unshaded is odd. the factors that are in diagonals is even.
d. Complete the chart by filling in each blank and writing an example for each rule.
| Rule | Example |
| odd times odd equals ___0dd_______ | 9 x 9 = 81. |
| even times even equals ___even_______ | 2 x 2 = 4. |
| even times odd equals ____even______ | 4 x 3 = 12. |
Answer: odd times odd equals = odd. even times even equals = even. even times odd equals = even.
Explanation: In the above-given question, given that, odd times odd equals = odd. even times even equals = even. even times odd equals = even. 9 x 9 = 81. 2 x 2 = 4. 4 x 3 = 12.
e. Explain how 7 × 6 = (5 × 6) + (2 × 6) is shown in the table
Answer: 7 x 6 = 42.
Explanation: In the above-given question, given that, 7 x 6 = 42. 5 x 6 = 30. 2 x 6 = 12. ( 5 x 6 ) + (2 x 6 ). 30 + 12 = 42.
f. Use what you know to find the product of 4 × 16 or 8 fours + 8 fours.
Answer: 4 x 16 = 64.
Explanation: In the above-given question, given that, 4 x 16 = 64. 8 fours + 8 fours. 8 x 4 + 8 x 4. 32 + 32. 64.
Question 2. Today in class, we found that n × n is the sum of the first n odd numbers. Use this pattern to find the value of n for each equation below. The first is done for you. a. 1 + 3 + 5 = n × n
b. 1 + 3 + 5 + 7 = n × n
Answer: 16 = 4 x 4.
Explanation: In the above-given question, given that, 16 = 4 x 4. 1 + 3 + 5 + 7 = n x n. n = 4. 4 x 4 = 16. 1 + 3 + 5 + 7 = 16.
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Eureka Math Grade 3 Module 3 Lesson 8 Answer Key
Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.
Engage NY Eureka Math 3rd Grade Module 3 Lesson 8 Answer Key
Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.
Eureka Math -Grade 3 Module 3 Lesson 8 Pattern Sheet Answer Key
Answer: 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 10 = 70, 7 x 5 = 35, 7 x 6 = 42, 7 x 5 = 35, 7 x 7 = 49, 7 x 5 = 35, 7 x 8 = 56, 7 x 5 = 35, 7 x 9 = 63, 7 x 5 = 35, 7 x 10 = 70, 7 x 6 = 42, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 7 = 49, 7 x 9 = 63, 7 x 7 = 49, 7 x 8 = 56, 7 x 6 = 42, 7 x 8 = 56, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 9 = 63, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 8 = 56, 7 x 9 = 63, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 6 = 42, 7 x 8 = 56, 7 x 9 = 63, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56.
Eureka Math Grade 3 Module 3 Lesson 8 Problem Set Answer Key
Question 1. Solve. a. (12 – 4) + 6 = __14____
Answer: (12 – 4) + 6 = 14.
Explanation: In the above-given question, given that, (12 – 4) = 8. 8 + 6 = 14.
b. 12 – (4 + 6) = ___2___
Answer: 12 – (4 + 6) = 2.
Explanation: In the above-given question, given that, 4 + 6 = 10. 12 – 10 = 2.
c. __5____ = 15 – (7 + 3)
Answer: 15 – (7 + 3) = 5.
Explanation: In the above-given question, given that, 7 + 3 = 10. 15 – 10 = 5.
d. __11____ = (15 – 7) + 3
Answer: (15 – 7) + 3 = 11.
Explanation: In the above-given question, given that, 15 – 7 = 8. 8 + 3 = 11.
e. ___30___ = (3 + 2) × 6
Answer: (3 + 2 ) x 6 = 30.
Explanation: In the above-given question, given that, 3 + 2 = 5. 5 x 6 = 30.
f. __15____ = 3 + (2 × 6)
Answer: 3 + ( 2 x 6 ) = 15.
Explanation: In the above-given question, given that, 2 x 6 = 12. 3 + 12 = 15.
g. 4 × (7 – 2) = __20____
Answer: 4 x ( 7 – 2 ) = 20.
Explanation: In the above-given question, given that, 7 – 2 = 5. 5 x 4 = 20.
h. (4 × 7) – 2 = __26____
Answer: (4 x 7) – 2 = 26. Explanation: In the above-given question, given that, 4 x 7 = 28. 28 – 2 = 26.
i. ___10___ = (12 ÷ 2) + 4
Answer: 4 + ( 12 / 2 ) = 10.
Explanation: In the above-given question, given that, 12 / 2 = 6. 4 + 6 = 10.
j. __2____ = 12 ÷ (2 + 4)
Answer: 12 / ( 2 + 4 ) = 2.
Explanation: In the above-given question, given that, 12 / 6 = 2. 2 + 4 = 6.
k. 9 + (15 ÷ 3) = __14____
Answer: 9 + ( 15 / 3 ) = 14.
Explanation: In the above-given question, given that, 15 / 3 = 5. 9 + 5 = 14.
l. (9 + 15) ÷ 3 = ___8___
Answer: (9 + 15) / 3 = 8.
Explanation: In the above-given question, given that, 9 + 15 = 24. 24 / 3 = 8.
m. 60 ÷ (10 – 4) = __10____
Answer: 60 / (10 – 4) = 10. Explanation: In the above-given question, given that, 10 – 4 = 6. 60 / 6 = 10.
n. (60 ÷ 10) – 4 = __2____
Answer: (60 / 10) – 4 = 2.
Explanation: In the above-given question, given that, (60 / 10) = 6. 6 – 4 = 2.
o. __37____ = 35 + (10 ÷ 5)
Answer: 35 + ( 10 / 5 ) = 37.
Explanation: In the above-given question, given that, 10 / 5 = 2. 35 + 2 = 37.
p. ___9___ = (35 + 10) ÷ 5
Answer: (35 + 10) / 5 = 9.
Explanation: In the above-given question, given that, 35 + 10 = 45. 45 / 5 = 9.
Question 2. Use parentheses to make the equations true. Answer:
Question 3. The teacher writes 24 ÷ 4 + 2 = __4 , __8__ on the board. Chad says it equals 8. Samir says it equals 4. Explain how placing the parentheses in the equation can make both answers true.
Answer: Yes, both the answers are true.
Explanation: In the above-given question, given that, The teacher writes 24 / 4 + 2 = 8 and 4 on the board. 24 / 4 = 6. 6 + 2 = 8. 4 + 2 = 6. 24 / 6 = 4. so both answers are true.
Question 4. Natasha solves the equation below by finding the sum of 5 and 12. Place the parentheses in the equation to show her thinking. Then, solve. 12 + 15 ÷ 3 = __17______
Answer: 12 + 15 / 3 = 17.
Explanation: In the above-given question, given that, Natasha solves the equation below by finding the sum of 5 and 12. 15 / 3 = 5. 12 + 5 = 17.
Question 5. Find two possible answers to the expression 7 + 3 × 2 by placing the parentheses in different places.
Answer: The two possible answers are 20 and 13.
Explanation: In the above-given question, given that, 7 + 3 x 2. 7 + 3 = 10. 10 x 2 = 20. 3 x 2 = 6. 7 + 6 = 13.
Eureka Math Grade 3 Module 3 Lesson 8 Exit Ticket Answer Key
Question 1. Use parentheses to make the equations true. a. 24 = 32 – 14 + 6
Answer: 24 = (32 – 14) + 6.
Explanation: In the above-given question, given that, 24 = 32 – 14 + 6. 32 – 14 = 18. 18 + 6 = 24.
b. 12 = 32 – 14 + 6
Answer: 12 = 32 – (14 + 6).
Explanation: In the above-given question, given that, 12 = 32 – 14 + 6. 14 + 6 = 20. 32 – 20 = 12.
c. 2 + 8 × 7 = 70
Answer: 70 = 70.
Explanation: In the above-given question, given that, 2 + 8 x 7. 2 + 8 = 10. 10 x 7 = 70.
d. 2 + 8 × 7 = 58
Answer: 58 = 58.
Explanation: In the above-given question, given that, 2 + 8 x 7. 7 x 8 = 56. 56 + 2 = 58.
Question 2. Marcos solves 24 ÷ 6 + 2 = ___6 and 3___. He says it equals 6. Iris says it equals 3. Show how the position of parentheses in the equation can make both answers true.
Explanation: In the above-given question, given that, Marcos solves 24 / 6 + 2. 24 / 6 = 4. 4 + 2 = 6. 6 + 2 = 8. 24 / 8 = 3. so both answers are true.
Eureka Math Grade 3 Module 3 Lesson 8 Homework Answer Key
Question 1. Solve. a. 9 – (6 + 3) = __0____
Answer: 9 – ( 6 + 3) = 0.
Explanation: In the above-given question, given that, 6 + 3 = 9. 9 – 9 = 0.
b. (9 – 6) + 3 = __6____
Answer: (9 – 6) + 3 = 6.
Explanation: In the above-given question, given that, (9 – 6) = 3. 3 + 3 = 6.
c. __8___ = 14 – (4 + 2)
Answer: 14 – (4 + 2) = 8.
Explanation: In the above-given question, given that, (4 + 2) = 6. 14 – 6 = 8.
d. ___12__ = (14 – 4) + 2
Answer: (14 – 4) + 2 = 12.
Explanation: In the above-given question, given that, (14 – 4) = 10. 10 + 2 = 12.
e. _42____ = (4 + 3) × 6
Answer: (4 + 3) x 6 = 42.
Explanation: In the above-given question, given that, (4 + 3) = 7. 7 x 6 = 42.
f. __22___ = 4 + (3 × 6)
Answer: (3 x 6) + 4 = 22.
Explanation: In the above-given question, given that, (3 x 6) = 18. 18 + 4 = 22.
g. (18 ÷ 3) + 6 = __12___
Answer: (18 / 3) + 6 = 12.
Explanation: In the above-given question, given that, (18 / 3) = 6. 6 + 6 = 12.
h. 18 ÷ (3 + 6)= __2___
Answer: 18 / (3 + 6) = 2.
Explanation: In the above-given question, given that, (3 + 6) = 9. 18 / 9 = 2.
Question 2. Use parentheses to make the equations true a. 14 – 8 + 2 = 4
Answer: 14 – (8 + 2) = 4. Explanation: In the above-given question, given that, 4 = 14 – 8 + 2. 8 + 2 = 10. 14 – 10 = 4.
b. 14 – 8 + 2 = 8
Answer: 8 = 8.
Explanation: In the above-given question, given that, 14 – 8 + 2 = 8. 14 – 8 = 6. 6 + 2 = 8.
c. 2 + 4 × 7 = 30
Answer: 30 = 30.
Explanation: In the above given question, given that, 30 = 2 + 4 x 7. 4 x 7 = 28. 28 + 2 = 30.
d. 2 + 4 × 7 = 42
Answer: 42 = 42.
Explanation: In the above given question, given that, 42 = 2 + 4 x 7. 2 + 4 = 6. 6 x 7 = 42.
e. 12 = 18 ÷ 3 × 2
Answer: 12 = 12.
Explanation: In the above-given question, given that, 12 = 18 / 3 x 2. 18 / 3 = 6. 6 x 2 = 12.
f. 3 = 18 ÷ 3 × 2
Answer: 3 = 3.
Explanation: In the above-given question, given that, 3 = 18 / 3 x 2. 3 x 2 = 6. 18 / 6 = 3.
g. 5 = 50 ÷ 5 × 2
Answer: 5 = 5.
Explanation: In the above-given question, given that, 5 = 50 / 5 x 2. 5 x 2 = 10. 50 / 10 = 5.
h. 20 = 50 ÷ 5 × 2
Answer: 20 = 20.
Explanation: In the above-given question, given that, 20 = 50 / 5 x 2. 50 / 5 = 10. 10 x 2 = 20.
Question 3. Determine if the equation is true or false.
| a. (15 – 3) ÷ 2 = 6 | Example: True |
| b. (10 – 7) × 6 = 18 | |
| c. (35 – 7) ÷ 4 = 8 | |
| d. 28 = 4 × (20 – 13) | |
| e. 35 = (22 – 8) ÷ 5 |
Answer: a. true. b. true. c. false. d. true. e. false.
Explanation: In the above-given question, given that, (15 – 3) / 2 = 6. (10 – 7) x 6 = 18. (35 – 7) / 4 = 7. 28 = 4 x (20 – 13). 2.8 = (22 – 8) / 5.
Question 4. Jerome finds that (3 × 6) ÷ 2 and 18 ÷ 2 are equal. Explain why this is true.
Answer: Yes, it is true.
Explanation: In the above-given question, given that, Jerome finds that (3 x 6) / 2 and 18 / 2 are equal. 3 x 6 = 18. so both of them are true.
Question 5. Place parentheses in the equation below so that you solve by finding the difference between 28 and 3. Write the answer 4 × 7 – 3 = __25______
Answer: The difference between 28 and 3 is 25.
Explanation: In the above-given question, given that, 4 x 7 – 3 = 25. 4 x 7 = 28. 28 – 3 = 25.
Question 6. Johnny says that the answer to 2 × 6 ÷ 3 is 4 no matter where he puts the parentheses. Do you agree? Place parentheses around different numbers to help you explain his thinking.
Answer: ( 2 x 6 ) / 3 = 4.
Explanation: In the above-given question, given that, 2 x 6 = 12. 12 / 3 = 4.
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Engage NY Eureka Math 3rd Grade Module 3 Lesson 18 Answer Key Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently.
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